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Images formed between the lens and the fovea appear blurry, as do images formed behind the fovea. Therefore, to focus on some object, you adjust your ciliary muscles until the image of that object is located on the fovea. Part A Joe first focuses his attention and his eyes on the tree. How to approach the problem Draw a picture of the object the tree , the lens, and the image it produces. Be sure to include the focal point of the lens. Where must the fovea be in your sketch if this object is in focus?

Is the focal point between the lens and the fovea, on the fovea, or behind the fovea? Image of the squirrel The squirrel is closer to the lens the eye than the tree. As long as Joe's eyes stay fixed on the tree, their focal length does not change. Using the lens equation, determine whether the image of the squirrel is closer to the lens than the image of the tree or farther away. Image of the mountain The mountain is farther from the lens the eye than the tree. Using the lens equation, determine whether the image of the mountain is closer to the lens than the image of the tree or farther away.

Note that curvature is different from radius of curvature. This is because he is nearsighted. But when Joe puts on his glasses, he can see the mountain clearly. Focusing on distant objects The image of a distant object like the mountain always forms at or very close to the focal point of the fovea-lens system. When Joe is looking at the most distant object he can see clearly, where is the focal point? The role of corrective lenses Nearsightedness and farsightedness are both caused by the fact that the ciliary muscles cannot make the focal length of the lens arbitrarily large or small.

The corrective lenses must make the image of the distant mountains form someplace that his eyes are naturally able to focus on. Two sources of coherent radio waves broadcasting in phase are located as shown below. Each grid square is 0. Part A At Point A is the interference between the two sources constructive or destructive? Path-length difference Since the two sources emit radio waves in phase, the only possible phase difference between the waves at various points is due to the different distances the waves have traveled to reach those points.

The difference in the distances traveled by the two waves from source to point of interest is termed the path-length difference. If the path-length difference is an integer multiple of the wavelength of the waves, one wave will pass through an integer number of complete cycles more than the other wave, placing the two waves back in perfect synchronization, resulting in constructive interference. If the path-length difference is a half-integer multiple of the wavelength, one wave will be one-half of a cycle, or , out of phase, resulting in destructive interference.

Find the path-length difference What is the distance from the left source to Point A,? What is the distance from the right source to Point A,? Enter the distances in meters separated by a comma. Find the path-length difference What is the distance from the left source to Point B,? What is the distance from the right source to Point B,?

Two speakers, emitting identical sound waves of wavelength 2. Express your answer using two significant figures. ANSWER: Part B Will the sound waves interfere constructively or destructively at the observer's location-or something in between constructive and destructive? At the observer's new location, what is the path difference for waves from the two speakers?

ANSWER: Part D Will the sound waves interfere constructively or destructively at the observer's location-or something in between constructive and destructive? The two antennas radiate in phase at a frequency of 4. All radio measurements are made far from the antennas. The smallest angle, reckoned north of east from the antennas, at which The smallest angle, reckoned north of east from the antennas, at which destructive interference of the two radio waves occurs, is closest to: ANSWER: Double Slit 1 Description: This problem explores double-slit interference maxima and minima.

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